Question

In the following circuit, calculate the electric current shown in ammeter, flowing through the $20.5\Omega$ resistor.

• A.
  3.66
• B.
  0.366
• C.
  0.3661
• D.
  0.36605

Answer 1

The correct option is D

0.36605
Given:
Source voltage, $V=7.98V$
Resistor 1, $R_1=20.5\Omega$
Resistor 2, $R_2=1.3\Omega$
Effective resistance in series, $R_{eff}=R_1+R_2$
$R_{eff}=20.5+1.3=21.8\Omega$
In series combination, the same current flows through all the resistors. So, the current through the resistor $R_1$ is the same as the total current in the circuit.
$\therefore$Current, $I=\frac{V}{R_{eff}}=\frac{7.98}{21.8}=0.36605A.$