In the following circuit employing pass transistor logic, all NMOS transistors are identical with a threshold voltage of 1 V. Ignoring the body-effect, the output voltages at P, Q and R are
A
4 V, 4 V, 4 V
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B
5 V, 4 V, 3 V
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C
4 V, 3 V, 2 V
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D
5 V, 5 V, 5 V
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Solution
The correct option is A 4 V, 4 V, 4 V
As we know that for proper operation VDS=VGS−VT VD−VS=VG−VS−VT ⇒VD=VG−VT
At P ⇒VD=VG−VT
Given VG for all transistor =5 V and VT for all transistors = 1 V ∴VDatP=VG−VT=5−1=4V VDatQ=VG−VT=5−1=4V VDatR=VG−VT=5−1=4V
According to the given options the only condition satisfied for the voltages at P, Q and R is only option (c).