Question

In the following circuit $i_1$ and $i_2$ are respectively (diodes are ideal)

• A. 0, 0
• B. 0, 5mA
• C. 5mA, 0
• D. 5mA, 5mA

Answer 1

The correct option is B

0, 5mA

we can get the above circuit if the diode is forward biased. After observing this circuit we get that,

$i=\frac{10}{2}=5mA=i_2$

$i_1=0$