Question

In the following circuit of PN junction diodes $D_1$, $D_2$ and $D_3$ are ideal then current, i is

• A. $\frac{E}{3R}$
• B. $\frac{E}{2R}$
• C. $\frac{2E}{3R}$
• D. Zero

Answer 1

The correct option is A $\frac{E}{3R}$

Diodes $D_1$ and $D_3$ are forward biased and $D_2$ is reverse biased so the circuit can be redrawn as follows.

Therefore, the net resistance in the circuit is $3R$ and the current is $\frac{E}{3R}$