Question

In the following circuit potential at point 'A' is zero. Which battery consumes or give maximum power?

Answer 1

$V_A=V_B=V_C=V_D=0$ as they are one junction

Similarly

$V_E=V_F=V_G=V_H=10$

as they are one junction

Applying loop law in $AEFB$ Applying loop rolw in $AEGC$

$10V+5V-1\times i_1=0$ $10-2i_2-15=0$

$15-i_1=0$ $5=2i_2$

$i=15A$ $i=\frac{5}{2}=2.5A$

Let $2-i_1-i_2=i_3$

Applying loop rule is $AEHD$

$10+5-3i_3=0$ $I-i_1-i_2=i_3$

$15-3i_3=0$ $I=i_1+i_2+i_3$

$i_3=5A$ $=22.5A$

Power delivered by $10V$ battery between $AE$

$P=IV$

$=22.5\times 10=225w$

Power delivered by $5V$ battery between $BF$

$P=IV$

$=15\times 5=75w$

Power delivered by $15V$ battery between $CG$

$P=IV$

$=\frac{5}{2}\times 15=27.5w$

Power delivered by $5V$ battery between $DH$

$P=IV$

$=5\times 5=25w$

Max.Power is delivered by $10V$ between $AE$