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Byju's Answer
Standard XII
Physics
Phasor Diagrams in AC Circuits
In the follow...
Question
In the following circuit, the current through the resistor
R
(
=
2
Ω
)
is
I
Amperes. The value of
I
is
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Solution
Due to balanced wheatstone bridge ABCEA
B
E
=
8
Ω
can be taken out.
R
A
C
=
(
1
+
2
)
(
2
+
4
)
(
1
+
2
)
+
(
2
+
4
)
=
18
9
=
2
Now, ACFGHA is a balanced Wheatstone bridge, hence
H
C
=
10
Ω
can be taken out.
R
A
G
=
6
∗
18
6
+
18
=
108
24
=
4.5
Ω
R
t
o
t
a
l
=
2
+
4.5
=
6.5
Ω
Hence, current
i
=
V
R
t
o
t
a
l
=
6.5
6.5
=
1
A
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