Question

In the following circuit, the switch $S$ is closed at $t=0$. The charge on the capacitor $C_1$ as a function of time will be given by $(C_{eq}=\frac{C_1{C}_2}{C_1+C_2})$.

• A. $C_{eq}E[1-exp(-t/R{C}_{eq}\left)\right]$
• B. $C_{1}E[1-exp(-tR/C_1\left)\right]$
• C. $C_{2}E[1-exp(-t/R{C}_2\left)\right]$
• D. $C_{eq}Eexp(-t/R{C}_{eq})$

Answer 1

Answer: (A)

$C_{eq}E[1-exp(-t/R{C}_{eq}\left)\right]$

the formula for charge varying with time in charging capacitor is

$Q=E\times C_{eq}(1-exp(\frac{-t}{R\times c_{eq}}\left)\right)$

as the equivalent capacitor is given in the question .so the correct option which matches is A.