Question

In the following common emitter configuration, an $npn$ transistor with current gain $\beta =100$ is used. The output voltage of the amplifier will be

• A. $1$ $mV$
• B. $0.1$ $V$
• C. $1$ $V$
• D. $10$ $V$

Answer 1

The correct option is C $1$ $V$

$voltagegain$ $=\frac{outputvoltage}{inputvoltage}$
$=>V_{out}=V_{in}$x$Voltagegain$
$=>V_{out}=V_{in}$x$\beta$x$resistancegain$
$=>V_{out}=V_{in}$x$\beta$x$\frac{R_{Load}}{R_{BaseEmitter}}$
$={10}^{-3}$x$100$x$\frac{10}{1}$
$=1V$