In the following compounds,

The order of acidity is

III > IV > I > II

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I > IV > III > II

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II > I > II > IV

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IV > III > I > II

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Solution

The correct option is D
IV > III > I > II

Electron - donation groups decrease while electron withdrawing groups increase the acidity of phenols. Therefore, the overall order of acidity is IV > III > I > II, i.e. option (d) is correct.

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Similar questions

Mark the correct order of decreasing acid strength of the following compounds.

(a) V > IV > II > I > III
(b) II > IV > I > III > V
(c) IV > V > III > II > I
(d) V > IV > III > II > I

Order of decreasing acidity of the following is

(I) HCOOH

(II) ${C H}_{3} C O O H$

(III) ${C l}_{2} C H C O O H$

(IV) ${C F}_{3} C O O H$

Q. Arrange the following compounds in order of increasing dipole moment.
(I) Toluene
(II) m - dichlorobenzene
(III) o - dichlorobenzene
(IV) p - dichlorobenzene

Order of decreasing acidity of

$(i) H C O O H (i i) C H_{3} C O O H (i i i) C l_{2} C H C O O H (i v) C F_{3} C O O H i s$

Q. Arrange the following compounds in decreasing order of their reactivity with sodium methoxide in methanol at

50^{\circ}

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In the following compounds, The order of acidity is

The correct option is D IV > III > I > II Electron - donation groups decrease while electron withdrawing groups increase the acidity of phenols. Therefore, the overall order of acidity is IV > III > I > II, i.e. option (d) is correct.

In the following compounds,

The order of acidity is

The correct option is D
IV > III > I > II

Electron - donation groups decrease while electron withdrawing groups increase the acidity of phenols. Therefore, the overall order of acidity is IV > III > I > II, i.e. option (d) is correct.