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Conditional Probability

In the follow...

Question

In the following diagram, $A B = A C$
Hence, $A F > A E$ .
If true enter 1 else 0

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Solution

Given in the figure,
$A B = A C$
$\Rightarrow F$ is the midpoint of $A C$
i.e $A F = F C$
$E$ splits $A B$ in the ratio $1 : 2$
$\Rightarrow A E \neq E B$
i.e $A F > A E$
$∴$ The statement is true.

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Similar questions

A D = A B

A E

A

∠ A B D > ∠ C

State whether the given statement is true/false:

In the following diagram, $A B = A C$ then which of the following is correct?

1. $A E > A F$

2. $A F > A E$

∠ B A C = 60^{0}

∠ A B C = 65^{0}

C F > A F

A B C D

A B

D C

∠ D > ∠ B

In $Δ A B C; B M ⊥ A C$ and $C N ⊥ A B$ ,
Hence,

$\frac{A B}{A C} = \frac{B M}{C N} = \frac{A M}{A N}$

If the above statement is true then mention answer as 1, else mention 0 if false

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