Question

In the following diagram; $AD=AB$ and $AE$
bisects angle $A$. Hence,$BE=DE$ .
State true or false:

• A. True
• B. False

Answer 1

The correct option is A True

In $△ABEand△AED$

$AE$ is common,$\angle BAE=\angle EAD$

$AB=AD$

So, by side angle side congruency theorem,

$△ABEand△AED$ the triangles are congruent.

So, $BE=ED$