In the following diagram, AP and BQ are equal and parallel to each other.
Prove that :
(i) Δ AOP ≅Δ BOQ.
(ii) AB and PQ bisect each other.
In △AOPand△BOQ
AP=BQ (given)
∠OAP=∠OBQ(each900
∠AOP=∠BOQ(vertically opposite angle)
△AOPis≅△BOQ (by AAS rule)
By CPCT
OP=OQ
AO=OB
Hence proved