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Centre of a Circle Lies on the Bisector of Angle between Two Tangents

In the follow...

Question

In the following diagram, PA and PB are tangents to the circle. Find the value of $∠ A O B$ .

24^{o}

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132^{o}

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66^{o}

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112^{o}

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Solution

The correct option is B $132^{o}$
$∠ A O B + ∠ A P B = 180^{o}$
$∠ A O B + 48^{o} = 180^{o}$
$∠ A O B = 180^{o} - 48^{o} = 132^{o}$

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Similar questions

∠ A P B = {(2 x + 3)}^{0} a n d ∠ A O B = {(3 x + 7)}^{0},

In the following diagram, and are tangents to the circle. Find the value of: a) $∠$ AOB b) $∠$ OBA given = 7 cm.

P

P A

P B

O

∠ P A B = 50^{\circ},

∠ A O B

O

P A

P B

A

B

l (P A) = 7 c m

l (P B)

c m

∠ A P B = 50^{\circ}

∠ A O B

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