In the following diagram- the charge and potential difference across 8 - F capacitance will be respectivelyA- 320 - C - 40 VB- 420 - C - 50 VC- 214 - C - 27 VD- 360 - C - 45 V

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Forward Bias

In the follow...

Question

In the following diagram, the charge and potential difference across 8 $μ F$ capacitance will be respectively

$320 μ C, 40 V$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$420 μ C, 50 V$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$214 μ C, 27 V$

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

$360 μ C, 45 V$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C
$214 μ C, 27 V$

Given circuit can be redrawn as follows, because capacitors, $9 μ F, 9 μ F a n d 7 μ F$ are short circuited. So they can be removed.

$V_{1} + V_{2} = 40 V a n d \frac{V_{1}}{V_{2}} = \frac{36}{18} = 2$
Hence $V_{1} = \frac{80}{3} V a n d V_{2} = \frac{40}{3} V$
Charge on $8 μ F$ capacitor $= 8 \times \frac{80}{3} = 213.3 μ F \approx 214 μ F$

Suggest Corrections

Similar questions

Q. In the following diagram, the charge and potential difference across

8 μ F

capacitance will be respectively (Approximately )

Q. A capacitor of unknown capacitance is connected across a battery of V volts . The charge stored in it is

360 μ C

. When potential across the capacitor is reduced by 120 V, the charge stored in it becomes

120 μ C

.
Calculate:
(i) The potential V and the unknown capacitance C.
(ii) What will be the charge stored in the capacitor, if the voltage applied had increased by 120 V?

Q. Three capacitors of capacities

8 μ F, 8 μ F

, and

4 μ F

are connected in series and a potential difference of

120

volt is maintained across the combination. Calculate the charge on capacitor of capacity

4 μ F

Q. Four capacitance are connected as shown in the adjoining figure. The charge and potential across 12

μ

capacitance will be respectively:

Two points have a potential difference of 10V. After connecting a conductor with zero resistance between the points, the final potential at each point becomes 25V. What could be their initial potentials?

Join BYJU'S Learning Program

In the following diagram, the charge and potential difference across 8 μF capacitance will be respectively

The correct option is C 214 μC, 27 V Given circuit can be redrawn as follows, because capacitors, 9μF, 9μF and 7μF are short circuited. So they can be removed. V1+V2=40V and V1V2=3618=2 Hence V1=803V and V2=403V Charge on 8μF capacitor =8×803=213.3 μF≈214μF

In the following diagram, the charge and potential difference across 8 $μ F$ capacitance will be respectively