Question

In the following equation,
$(a+bx)-(cx-d)=mx$, the value of $x$, is

• A. $-\frac{(a+d)}{(b-c-m)}$
• B. $\frac{(a-d)}{(b+c-m)}$
• C. $-\frac{(a+d)}{(b-c+m)}$
• D. $\frac{(a+d)}{(b-c-m)}$

Answer 1

The correct option is A $-\frac{(a+d)}{(b-c-m)}$

The given equation is
$(a+bx)-(cx-d)=mx$.

$\Rightarrow a+bx-cx+d=mx$

Transposing $a$ and $d$ from LHS to RHS and transposing $mx$ from RHS to LHS, we get,

$bx-cx-mx=-a-d$

$(b-c-m)x=-(a+d)$

Transposing $(b-c-m)$ from LHS to RHS, we get,
$x=-\frac{(a+d)}{(b-c-m)}$