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Question

In the following expansion find which is the greatest term:
(3+2x)15 when x=52.

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Solution

(3+2x)15=315(1+23x)15

Tr+1=15r+1r53×Tr

For Tr+1>Tr when 805r>3r or r<10

Therefore T10 and T11 are equal and the greatest terms

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