In the following figure, a rectangle ABCD enclosed three circles. If BC =14 cm, find the area of the shaded portion (Take $π = 3 \frac{1}{7})$

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Solution

In rectangle ABCD,

BC =14 cm

$∴$ Radius of each circle $= \frac{14}{2} = 7 c m$

$∴$ Length of rectangle $= (7 + 7 + 7) \times 2$

=42 cm

Now area of rectangle $= l \times b = 42 \times 14$

$= 588 c m^{2}$

and area of 3 circles $= 3 \times π r^{2}$

$= 3 \times \frac{22}{7} \times 7 \times 7 = 462 c m^{2}$

$∴$ Area of shaded portion

$= 588 - 462 = 126 c m^{2}$

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In the following figure, a rectangle ABCD enclosed three circles. If BC =14 cm, find the area of the shaded portion (Take π=317)

In rectangle ABCD, BC =14 cm ∴ Radius of each circle =142=7cm ∴ Length of rectangle =(7+7+7)×2 =42 cm Now area of rectangle =l×b=42×14 =588cm2 and area of 3 circles =3×πr2 =3×227×7×7=462cm2 ∴ Area of shaded portion =588−462=126cm2

In the following figure, a rectangle ABCD enclosed three circles. If BC =14 cm, find the area of the shaded portion (Take $π = 3 \frac{1}{7})$