The correct option is
A 5Given:
ABCD is a
∥gm, therefore
AB=CD and AD=BC [Opposite sides of ∥gm are equal]
4x=6y+2⇒4x−6y=2
2x−3y=1→(1)
& 4y=3x−3⇒3x−4y=3→(2)
Multiply (1) by 3 and (2) by 2 and subtracting we get,
6x−9y=3
6x−8y=6
------------------------
0−y=−3
y=3
From (1), 2x−3×3=1
⇒x=9+12=5
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