In the following figure ABCD is a trapezium in which $A B ∥ D C$ . Find the measure of $∠ C$ .

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Solution

It is given that ABCD is a trapezium.

$A B ∥ D C$ .

$∴ ∠ C + ∠ B = 180^{\circ} [S u m o f c o i n t e r i o r a n g l e s i s 180^{\circ}]$

$\Rightarrow ∠ C + 120^{\circ} = 180^{\circ}$

$\Rightarrow ∠ C = 180^{\circ} - 120^{\circ} = 60^{\circ}$

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