In the following figure ABCD is a trapezium in which $A B ∥ D C$ . Find the measure of $∠ C$ .
(2 marks)

Open in App

Solution

It is given that ABCD is a trapezium.

So, $A B ∥ D C$ .

(0.5 mark)

$∴ ∠ C + ∠ B = 180^{\circ} [S u m o f c o i n t e r i o r a n g l e s i s 180^{\circ}]$

$\Rightarrow ∠ C + 120^{\circ} = 180^{\circ}$

$\Rightarrow ∠ C = 180^{\circ} - 120^{\circ} = 60^{\circ}$

(1.5 marks)

Suggest Corrections

Similar questions

In the adjoining figure, ABCD is a trapezium in which AB II DC. If $∠ A = 55^{\circ} a n d ∠ B = 70^{\circ}$ , find $∠ C ∠ D$ .

In the following figure ABCD is a trapezium in which $A B ∥ D C$ . Find the measure of $∠ C$ .

A B ∥ D C

∠ C

\frac{A O}{O C} = \frac{B O}{O D} = \frac{1}{2} a n d A B = 5 c m

Join BYJU'S Learning Program