In the following figure, AD and EF are medians. What’s the length of FC?

4 cm

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3 cm

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2 cm

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1 cm

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Solution

The correct option is C 2 cm

Since AD is the median, BD = DC.
So, CD = 4 cm

Also, since EF is the median, $D F = C F = \frac{C D}{2} = \frac{4}{2} = 2 cm$

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In the following figure, AD and EF are medians. What’s the length of FC?

The correct option is C 2 cm Since AD is the median, BD = DC. So, CD = 4 cm Also, since EF is the median, DF=CF=CD2=42=2 cm

The correct option is C 2 cm

Since AD is the median, BD = DC.
So, CD = 4 cm

Also, since EF is the median, $D F = C F = \frac{C D}{2} = \frac{4}{2} = 2 cm$