In the following figure all the bulbs connected are identical. The bulb that lights most brightly is :
A
only1
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B
only2
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C
4 and 5
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D
2 and 4
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Solution
The correct option is C4 and 5 The bulb that has maximum power through it lights most brilliantly.The power through any bulb in the circuit is i2R.
where, i is the current passing through the given bulb, R is the resistance of the bulb, same for all of them.
Since same current is present in both bulbs 4 and 5, and it further divides into bulbs 3, 1, and 2, the power and hence brightness is maximum for bulbs 4 and 5.