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Question

In the following figure, AXY = AYX. If BXAX=CYAY, show that triangle ABC is isosceles.

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Solution

Given,
∠AXY = ∠AYX
⇒AX = AY

Also, BX/AX = CY/AY
⇒BX/AX + 1 = CY/AY + 1
⇒BX+AX/AX = CY+AY/AY
⇒AB/AX = AC/AY
⇒AB/AY = AC/AY [∵ AX = AY]
⇒AB = AC

Thus, the given triangle is isosceles.

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