Question

In the following figure, \(\angle\)\(POQ\) = \(\angle\)\(QOA\) = \(45^\circ\).
Then OQ is the angle bisector of \(\angle\)\(POA\).

• A. 45°
• B. 60°

Answer 1

The correct option is A

45°

SInce $\angle$POQ = $\angle$QOA= ${45}^{\circ }$, OQ is angle bisector of $\angle$POA.