In the following figure, CE is drawn parallel to diagonal DB of the quadrilateral ABCD which meets AB produced at point E .Then △ADE and quadrilateral ABCD are equal in area.If true enter 1 else 0.
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Solution
CE is parallel to diagonal DB, and triangle BDE and BDC is drawn between the parallel line and upon the same base BD. So, Area of triangle BDE and BDC is equal. △ADE=△ADB+△DBE △ADE=△ADB+△BDC =Quad. ABCD