Question 4
In the following figure, DE||AC and DF||AE. Prove that $\frac{B F}{F E} = \frac{B E}{E C}$ .

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Solution

In $Δ A B C, D E | | A C$ (Given)
$∴ \frac{B D}{D A} = \frac{B E}{E C} . . . (i)$ [By using Basic Proportionality Theorem]
In $Δ A B E$ , DF || AE (Given)
$∴ \frac{B D}{D A} = \frac{B F}{F E} . . . (i i)$ [By using Basic Proportionality Theorem]
From equation (i) and (ii), we get
$\frac{B E}{E C} = \frac{B F}{F E}$

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Question 4
In the following figure, DE||AC and DF||AE. Prove that $\frac{B F}{F E} = \frac{B E}{E C}$ .

Question 4
In the following figure, DE||AC and DF||AE. Prove that $\frac{B F}{F E} = \frac{B E}{E C}$ .

\frac{B F}{F E} = \frac{B E}{E C}

D E ∥ A C

D F ∥ A E

\frac{B F}{F E} = \frac{B E}{E C}

D E | | A C

D F | | A E

\frac{B F}{F E} = \frac{B E}{E C}

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