Question

In the following figure, $DE\parallel AB$. If $AD=7cm,CD=5cm$ and $BC=18cm$, find $CE$.

Answer 1

In $△ABC,DE\parallel AB$

$\frac{CD}{CA}=\frac{CE}{CB}$ (Corollary to B.P.T.)

$\Rightarrow \frac{5}{12}=\frac{CE}{18}$

$\Rightarrow 12\times CE=5\times 18$

$\Rightarrow CE=\frac{5\times 18}{12}=\frac{15}{2}$

$\therefore CE=7.5cm$