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In the follow...

Question

In the following figure, $D E ∥ B C, A D$
=5.6 cm, AE = (x + 1) cm, DB = 2.8 cm and EC = (x - 1) cm. Find x

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Solution

$D E ∥ B C \Rightarrow \frac{A D}{D B} = \frac{A E}{E C}$
$\Rightarrow \frac{A E}{E C} = \frac{5.6}{2.8} = \frac{x + 1}{x - 1} \Rightarrow 2 = \frac{x + 1}{x - 1}$
$\Rightarrow 2 x - 2 = x + 1 \Rightarrow x = 3$

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