![](https://search-static.byjusweb.com/question-images/byjus/infinitestudent-images/ckeditor_assets/pictures/398917/original_154961.png)
In
ΔABC,
∠ABC+∠BCA+∠CAB=180∘ [Angle sum property of triangle]
⇒64∘+∠BCA+52∘=180∘ ⇒∠BCA=180∘−64∘−52∘=64∘ ∠FAE=∠BCA [
∵ Alternate angles;
AE∥BC, AC is the transversal]
⇒∠FAE=64∘ Now,
∠FAE+x=180∘ [Adjacent angles in a parallelogram are supplementary]
⇒x=180∘−64∘∴x=116∘