Question

In the following figure, fing $\angle 1+\angle 2+\angle 3+\angle 4+\angle 5+\angle 6+\angle 7$

• A. ${360}^0$
• B. ${720}^0$
• C. ${840}^0$
• D. ${540}^0$

Answer 1

Answer: (D)

${540}^0$

In this figure seven angles sides
then (n-1)$\times$90=$\angle$1+$\angle$2+$\angle$3+$\angle$4+$\angle$5+$\angle$6+$\angle$7=(7-1)$\times$90=540 ${}^0$