In the following figure, if AC and BD are diameters of the circle with centre O, then $\frac{A D}{B C}$ = ?

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Solution

The correct option is A
1

$In △ A O D and △ B O C,$

$O A = O B$ (radii)

$O C = O D$ (radii)

$∠ A O D = ∠ B O C$ (vertically opposite angles)

$∴ △ A O D ≅ △ B O C$
(by SAS congruency rule)

$\Rightarrow A D = B C$ (CPCT)

$∴ \frac{A D}{B C}$ = 1

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