In the following figure, if AC = BD, then prove that AB = CD.

Open in App

Solution

From the figure, it can be observed that

AC = AB + BC

BD = BC + CD

It is given that AC = BD

AB + BC = BC + CD (1)

According to Euclid’s axiom, when equals are subtracted from equals, the remainders are also equal.

Subtracting BC from equation (1), we obtain

AB + BC − BC = BC + CD − BC

AB = CD

Suggest Corrections

494

Similar questions

In the given figure, $A C = B D$ . Prove that $A B = C D$ .

A C = B D,

A B = C D

O

A B

C D

A C = B D

A C | | B D

Join BYJU'S Learning Program