Question

In the following figure, if $\angle AQB={80}^o$, then find $m\left(arcAXB\right)$.

Answer 1

$m\left(arcAXB\right)=2\times m\angle AQB$

$\Rightarrow m\left(arcAXB\right)=2\times {80}^{\circ }={160}^{\circ }$