Question

In the following figure, if $\angle P={60}^{\circ }$

Find $\angle Q$.

• A. ${60}^{\circ }$
• B. ${120}^{\circ }$
• C. ${80}^{\circ }$
• D. ${100}^{\circ }$

Answer 1

The correct option is B

${120}^{\circ }$

PS || QR

so, $\angle P+\angle Q={180}^{\circ }$ (interior angles on the same side of transversal)

${60}^{\circ }+\angle Q={180}^{\circ }$

$\angle Q={120}^{\circ }$