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Question

In the following figure, if OA = OD and 1=2. Prove that ΔOCB is an isosceles triangle.

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Solution

Given: OA = OD and 1=2
In OCA and OBD
OA = OD (Given)
AOC=DOB (Vertically opposite angles)
1=2 Given180-1=2-180CAO=BDO
CAOBDO (By ASA)
Thus, by corresponding parts of congruent triangles, we have
OC = OB
Hence, ΔOCB is an isosceles triangle.

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