Question

In the following figure, if OQ is angle bisector of ∠POA, then 2 $\times$ ∠POQ = _____

• A. ∠QOA
• B. ∠ POQ + QOA
• C. 90${}^{\circ }$
• D. ∠POA

Answer 1

Answer: (B), (C), (D)

The correct options are
B ∠ POQ + QOA
C 90${}^{\circ }$
D ∠POA

An angle bisector divides an angle into two equal halves.
$\therefore$ ∠POQ = ∠QOA = ${45}^{\circ }$
2 $\times$ ∠POQ = 2 $\times$ 45 = ${90}^{\circ }$
∠POQ + ∠QOA = 45 + 45 = ${90}^{\circ }$
∠POA = ∠POQ + ∠QOA = 45 + 45 = ${90}^{\circ }$