In the following figure- if OQ is angle bisector of - POA- then 2 - POQ cannot be equal toA- - POAB- 90-C- - POQ - QOAD- - Q O A

An angle bisector divides an angle into two equal halves. ∴ nbsp;∠POQ nbsp; = ∠QOA = 45 ^∘ 2 × ∠POQ = nbsp; 2 nbsp; × nbsp;45 = 90 ^∘ ∠POQ + ∠QOA = 45 ...

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Standard VI

Mathematics

Construction to Bisect a Given Angle

In the follow...

Question

In the following figure, if OQ is angle bisector of ∠POA, then 2 $\times$ ∠POQ cannot be equal to _____.

∠POA

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^{\circ}

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∠ POQ + ∠ QOA

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∠QOA

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Solution

The correct option is D ∠QOA
An angle bisector divides an angle into two equal halves.
$∴$ ∠POQ = ∠QOA = $45^{\circ}$
2 $\times$ ∠POQ = 2 $\times$ 45 = $90^{\circ}$
∠POQ + ∠QOA = 45 + 45 = $90^{\circ}$
∠POA = ∠POQ + ∠QOA = 45 + 45 = $90^{\circ}$

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Similar questions

In the following figure, if OQ is angle bisector of $∠ P O A$ , then $∠ P O Q$ will be equal to ___.

Q. In the following figure, if OQ is angle bisector of ∠POA, then 2

\times

∠POQ cannot be equal to _____.

In the following figure, if OQ is angle bisector of $∠$ POA, then $∠$ POQ will be equal to ___.

In the following figure, $\angle$$POQ$ = $\angle$$QOA$ = $45^\circ$.
Then OQ is the angle bisector of $\angle$$POA$.

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In the following figure, if OQ is angle bisector of ∠POA, then 2 × ∠POQ cannot be equal to _____.

The correct option is D ∠QOAAn angle bisector divides an angle into two equal halves. ∴ ∠POQ = ∠QOA = 45∘ 2 × ∠POQ = 2 × 45 = 90∘ ∠POQ + ∠QOA = 45 + 45 = 90∘ ∠POA = ∠POQ + ∠QOA = 45 + 45 = 90∘

In the following figure, if OQ is angle bisector of ∠POA, then 2 $\times$ ∠POQ cannot be equal to _____.

The correct option is D ∠QOA
An angle bisector divides an angle into two equal halves.
$∴$ ∠POQ = ∠QOA = $45^{\circ}$
2 $\times$ ∠POQ = 2 $\times$ 45 = $90^{\circ}$
∠POQ + ∠QOA = 45 + 45 = $90^{\circ}$
∠POA = ∠POQ + ∠QOA = 45 + 45 = $90^{\circ}$