Question

In the following figure, if the tension in the string AB is $51$N, then the tension in the string BC will be?

Answer 1

From the horizontal forces

$51\sin {30}^{\circ }=\sin {60}^{\circ }$

$51\times \frac{1}{2}=T\times \frac{\sqrt{3}}{2}$

$T=\frac{51}{\sqrt{3}}=29.4$

$=30N$(approx.)