Question

In the following figure, in $\Delta ABC,\angle B={90}^o,\angle C={60}^o,\angle A={30}^o,AC=16cm$.
Find $BC$ (in $cm$).

Answer 1

$\Delta ABC,\angle A={30}^o,\angle B={90}^o,\angle C={60}^o$
$\therefore \Delta ABC$ is a ${30}^o-{60}^o-{90}^o$ triangle and AC is hypotenuse.
So, $BC=\frac{1}{2}\times AC$ (Side opposite to ${30}^o$)
$=\frac{1}{2}\times 16=8cm$
$\therefore BC=8cm$