Question

In the following figure, in $△ABC,BC=1,AC=2,\angle B={90}^{\circ }$. Find the value of $\sin \theta$

Answer 1

Given: In $△ABC$,
$BC=1,AC=2$ and $\angle B={90}^{\circ }$
To find: $\sin \theta$
We know that,
$\sin \theta =\frac{BC}{AC}$
$\therefore \sin \theta =\frac{1}{2}$