In the following figure, it is given that AB∥DE and BC=EC. △ABC≅△DEC by ___ congruence rule.
In △ABC and △DEC,
BC=EC [given] ∠ABC=∠DEC [alternate interior angles] ∠ACB=∠DCE [vertically opposite angles]
Therefore, △ABC≅△DEC [by ASA congruence condition]
In the given figure, if OA = BO and OC = OD, then, ΔAOD ≅ ΔBOC by __ congruence rule.