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Question
In the following figure, it is given that AB ∥ DE and BC = EC. △ABC ≅ △DEC by __ congruence rule
In the following figure, it is given that AB ∥ DE and BC = EC. △ABC ≅ △DEC by
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Solution
In △ABC and △DEC,
BC = EC (given)
∠ABC = ∠DEC (alternate interior angles)
∠ACB = ∠DCE (vertically opposite angles)
Therefore, △ABC ≅ △DEC (by ASA congruence condition)
In △ABC and △DEC,
BC = EC (given)
∠ABC = ∠DEC (alternate interior angles)
∠ACB = ∠DCE (vertically opposite angles)
Therefore, △ABC ≅ △DEC (by ASA congruence condition)
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