Question

In the following figure, line $PY$ $\parallel$ side $BC,AP=3,PB=6,AY=5,YC=x$, then find $x$.

Answer 1

Since $PQ\parallel BC$,

Thus using Basic Proportionality Theorem

$\frac{AY}{YC}=\frac{AP}{PB}$

$\Rightarrow \frac{5}{x}=\frac{3}{6}$

$\Rightarrow 3x=30$, cross multiply

$\therefore x=10$