We have, two parallelograms ABDH and CEFG.
In parallelogram ABDH,
∠ABD+∠BDH=180∘ [∵ adjacent angles of a parallelogram are supplementary]
⇒∠BDH=180∘−130∘⇒∠BDH=50∘……(i)
In parallelogram CEFG,
∠GCE=∠GFE [∵Opposite angles are equal]
⇒∠GCE=30∘……(ii)
In ΔOCD, by using angle sum property, ∠OCD+∠ODC+∠COD=180∘
⇒50∘+30∘+x=180∘ [From (i) and (ii)]
⇒x=180∘−80∘=100∘