Question

In the following figure of an isosceles triangle, find the value of 'x'?

• A. 6 cm
• B. 4 cm
• C. 8 cm
• D. 2 cm

Answer 1

The correct option is A 6 cm

In the given figure, $△AEB$ is the Right angle triangle at $E$, $AB=9$ cm and $AE=7$ cm

Then, $(BE{)}^2=(AB{)}^2-(AE{)}^2=(9{)}^2-(7{)}^2=81-49=32$ cm

Also, $△BEC$ is the Right angle triangle at $E$, $EC=2$ cm and $BC=x$ cm

$\therefore (BC{)}^2=(BE{)}^2+(CE{)}^2$

$x^2=32+(2{)}^2=32+4=36$

$x=6$ cm