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Question

In the following figure QTPR and QS=PS. If TQR=40o and RPS=20o then value of x is?
719437_0240ae9a48634292b1ff5911ab4115b5.png

A
80o
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B
25o
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C
15o
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D
35o
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Solution

The correct option is C 15o
In ΔPQS,
QS=PS
Q=P=40o+x
In ΔRQT,
R=180o(90o+40o)
R=50o
In ΔPQR,
40o+x+40o+x+20o+50o=180o
x=30o2=15o
Option (3).

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