In the following figure, R = 50.4Ω. EMF of the cell E is 1.2 V. The value and direction of current are given. If B is at zero potential, what is the potential at A?
A
61.00V
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B
59.28V
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C
-59.28V
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D
-61.00V
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Solution
The correct option is C -59.28V Given: Voltage of cell E, VE = 1.2 V. Current flowing in the path, I = 1.2 A. Resistance R = 50.4Ω. Using Kirchoff's law's sign conventions as shown below: VE−(I×R)−VA=0 ⟹1.2−(1.2×50.4)=VA hence, VA=−59.28V.