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Question

In the following figure shown, a liquid is filled into the vessel up to a height h and the forces exerted against the liquid by the walls of the vessel are shown by arrows, the force being everywhere perpendicular to the walls of the vessel. For this situation, mark out the correct statement(s)

156923_24a089543a894b4884cae92f80960707.png

A
the horizontal component of the forces on the left and right side inclined faces will cancel each other
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B
the weight of the section lettered A is supported by vertical component of forces acting on the inclined faces
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C
force exerted by the liquid on the base of the vessel is greater than (p0+ρgh) A where ρ is the density of the liquid and A is base area of the vessel
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D
net force exerted by liquid on the base of the vessel is in the vertical downward direction
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Solution

The correct options are
A the weight of the section lettered A is supported by vertical component of forces acting on the inclined faces
B force exerted by the liquid on the base of the vessel is greater than (p0+ρgh) A where ρ is the density of the liquid and A is base area of the vessel
C the horizontal component of the forces on the left and right side inclined faces will cancel each other
D net force exerted by liquid on the base of the vessel is in the vertical downward direction
The liquid in the vessel is in equilibrium. Only horizontal forces acting on the liquid are acting on the inclined faces. Thus they must be equal and opposite to each other to cancel.
Normal forces act from the bottom to top of the vessel. The weight of the inclined section could only be supported by these forces.
Since the horizontal force acting liquid cancel each other, so would the horizontal forces acting on vessel by liquid. Thus the net force exerted by liquid on base of vessel is vertically downwards.

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