In the following figure- shows a kite in which B C D is the shape of a quadrant of a circle of radius 42 cm - A B C D is a square and - C E F is an isosceles right angled triangle whose equal sides are 6 cm long- Find the area of the shaded region-

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Standard X

Mathematics

Areas of Combination of Plane Figures

In the follow...

Question

In the following figure, shows a kite in which BCD is the shape of a quadrant of a circle of radius 42 cm. ABCD is a square and Δ CEF is an isosceles right angled triangle whose equal sides are 6 cm long. Find the area of the shaded region.

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Solution

We will find the area of the shaded region as shown below,

Area of the shaded region = area of quadrant + area of isosceles triangle ……..(1)

Substituting we get,

Therefore, area of the shaded region is.

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In the following figure, shows a kite in which BCD is the shape of a quadrant of a circle of radius 42 cm. ABCD is a square and Δ CEF is an isosceles right angled triangle whose equal sides are 6 cm long. Find the area of the shaded region.

We will find the area of the shaded region as shown below, Area of the shaded region = area of quadrant + area of isosceles triangle ……..(1) Substituting we get, Therefore, area of the shaded region is.

We will find the area of the shaded region as shown below,

Area of the shaded region = area of quadrant + area of isosceles triangle ……..(1)

Substituting we get,

Therefore, area of the shaded region is.