In the following figure, the area of the pedal triangle is -
A
12R2.sin A.sin B.sin C
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B
12R2.sin 2A.sin 2B.sin 2C
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C
12R2.cos A.cos B.cos C
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D
None of these
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Solution
The correct option is B12R2.sin 2A.sin 2B.sin 2C Since, area of a triangle =12(product of the sides)×sine of the included angle) =12Rsin2B⋅sin(180°−2A) =12R2sin2A⋅sin2B⋅sin2C